An electron carrying a charge of \(1.6 \times 10^{-19}\,\mathrm{C}\) revolves in a circle at \(10^{16}\) revolutions per second. The equivalent current is:

Electron Revolving Current – Numerical Solution

Question: An electron carrying a charge of \(1.6 \times 10^{-19}\,\mathrm{C}\) revolves in a circle at \(10^{16}\) revolutions per second. The equivalent current is:

a) \(1.6 \times 10^{-2}\,\mathrm{A}\)

b) \(1.6 \times 10^{-3}\,\mathrm{A}\)

c) \(1.6 \times 10^{-4}\,\mathrm{A}\)

d) \(1.9 \times 10^{-3}\,\mathrm{A}\)

Detailed Solution:

An electron revolving at \(N\) revolutions per second constitutes a current

\[ I = N \times e \]

Given:

• \(N = 10^{16}\,\mathrm{s^{-1}}\)
• \(e = 1.6 \times 10^{-19}\,\mathrm{C}\)

Therefore,

\[ I = 10^{16} \times 1.6 \times 10^{-19} = 1.6 \times 10^{-3}\,\mathrm{A} \]

Correct answer: (b) \(1.6 \times 10^{-3}\,\mathrm{A}\)